Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 6 - Section 6.2 - Trigonometry of Right Triangles - 6.2 Exercises - Page 489: 54

Answer

a. 93,431 ft b. 86,628 ft

Work Step by Step

See sketch below. a. $\displaystyle \sin 22^{o}=\frac{35,000}{d} \ \Rightarrow \ d=\frac{35,000}{\sin 22^{o}}$ $ d\approx$93431.3506894$\approx$ 93,431 ft b. $\displaystyle \tan 22^{o}=\frac{35,000}{x} \ \Rightarrow \ x=\frac{35,000}{\tan 22^{o}}$ $ x\approx$ 86628.0398696$\approx $86,628 ft
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.