Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 6 - Section 6.2 - Trigonometry of Right Triangles - 6.2 Exercises - Page 488: 49

Answer

$63.7$

Work Step by Step

Let c be the shared side. In the triangle with the given acute angle of $60^{o}$, c is the hypotenuse, 50 is the side opposite the angle. $\displaystyle \sin 60^{o}=\frac{50}{c}\ \Rightarrow\ c=\frac{50}{\sin 60^{o}}$ In the triangle with the given acute angle of $65^{o}$, c is the leg opposite the angle, x is the hypotenuse $\displaystyle \sin 65^{o}=\frac{c}{x}\ \Rightarrow\ x=\frac{c}{\sin 65^{o}}=\frac{50}{\sin 60^{o}\sin 65^{o}}$ $\approx$63.7035538531 $x\approx 63.7$
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