Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 6 - Section 6.2 - Trigonometry of Right Triangles - 6.2 Exercises - Page 488: 35

Answer

$\left( \cos \dfrac {\pi }{4}+\sin \dfrac {\pi }{6}\right) ^{2}=\dfrac {3+2\sqrt {2}}{4}\approx 1.457$

Work Step by Step

$\left( \cos \dfrac {\pi }{4}+\sin \dfrac {\pi }{6}\right) ^{2}=\left( \dfrac {\sqrt {2}}{2}+\dfrac {1}{2}\right) ^{2}=\dfrac {\left( \sqrt {2}\right) ^{2}+1^{2}+2\times 1\times \sqrt {2}}{4}=\dfrac {3+2\sqrt {2}}{4}\approx 1.457$
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