Answer
1
Work Step by Step
$\sin \alpha \cos \theta +\cos \alpha \sin \theta =\sin \left( \alpha +\theta \right) \Rightarrow \sin 30^0\cos 60^0+\cos {30^0}\sin 60^0=\sin \left( 30^0+60^0\right) =\sin 90^0=1$
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 6 - Section 6.2 - Trigonometry of Right Triangles - 6.2 Exercises - Page 488: 31
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