Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 6 - Section 6.2 - Trigonometry of Right Triangles - 6.2 Exercises - Page 488: 33

Answer

$\left( \cos 30\right) ^{2}-\left( \sin 30\right) ^{2}=\dfrac {1}{2}$

Work Step by Step

$\left( \cos \alpha \right) ^{2}-\left( \sin \alpha \right) ^{2}=\cos ^{2}\alpha \Rightarrow \left( \cos 30\right) ^{2}-\left( \sin 30\right) ^{2}=\cos \left( 2\times 30\right) =\cos 60=\dfrac {1}{2}$
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