Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 6 - Section 6.2 - Trigonometry of Right Triangles - 6.2 Exercises - Page 487: 4

Answer

$\sin\theta=\dfrac{7}{25}$ $\cos\theta=\dfrac{24}{25}$ $\tan\theta=\dfrac{7}{24}$ $\csc\theta=\dfrac{25}{7}$ $\sec\theta=\dfrac{25}{24}$ $\cot\theta=\dfrac{24}{7}$

Work Step by Step

The triangle is shown in the attached image below. $\sin\theta=\dfrac{opposite}{hypotenuse}=\dfrac{7}{25}$ $\cos\theta=\dfrac{adjacent}{hypotenuse}=\dfrac{24}{25}$ $\tan\theta=\dfrac{opposite}{adjacent}=\dfrac{7}{24}$ $\csc\theta=\dfrac{hypotenuse}{opposite}=\dfrac{25}{7}$ $\sec\theta=\dfrac{hypotenuse}{adjacent}=\dfrac{25}{24}$ $\cot\theta=\dfrac{adjacent}{opposite}=\dfrac{24}{7}$
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