Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 6 - Section 6.2 - Trigonometry of Right Triangles - 6.2 Exercises - Page 487: 26

Answer

$sin\theta=\frac{\sqrt3}{2}$ $cos\theta=\frac{1}{2}$ $cot\theta=\frac{1}{\sqrt3}$ $csc\theta=\frac{2}{\sqrt3}$ $sec\theta=2$

Work Step by Step

To identify all the remaining trigonometric ratios we will use the trigonometric identities and according to those ratios we will determine angle degrees to graph the triangle. Step by step, we will first identify one of the trigonometric identities and then calculate: $tan\theta = \sqrt3$; According to Trigonometric Ratios Table, we can easily determine that $\theta=60°$. Which means that we have $30-60-90$ triangle(Also see the image) So, $\theta=60°$ Again according to the trigonometric ratios table: $sin60°=\frac{\sqrt3}{2}$ $cos60°=\frac{1}{2}$ $cot\theta=\frac{cos\theta}{sin\theta}=\frac{1}{2}\times\frac{2}{\sqrt3}=\frac{1}{\sqrt3}$ $csc\theta=\frac{1}{sin\theta}=\frac{2}{\sqrt3}$ $sec\theta=\frac{1}{cos\theta}=2$
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