Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 6 - Section 6.2 - Trigonometry of Right Triangles - 6.2 Exercises - Page 487: 23

Answer

The other ratios: cos: $\frac{6}{\sqrt 61}$ sin: $\frac{5}{\sqrt 61}$ sec: $\frac{\sqrt 61}{6}$ csc: $\frac{\sqrt 61}{5}$ cot: $\frac{6}{5}$

Work Step by Step

Remember the acronym, "SOHCAHTOA" $sine=\frac{opp}{hyp}$ $cos=\frac{adj}{hyp}$ $tan=\frac{opp}{adj}$ And the opposites of these functions switch everything. Since we are given $tan=\frac{5}{6}$, we know that our opposite is 5 and our adjacent is 6. From there we can calculate a hypotenuse of $\sqrt 61$ (pythagorean theorem: $5^2 + 6^2 = c^2$ From there, you can find the remaining ratios.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.