Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 6 - Section 6.2 - Trigonometry of Right Triangles - 6.2 Exercises - Page 487: 3

Answer

$\sin\theta=\dfrac{4}{5};$ $\cos\theta=\dfrac{3}{5}$ $\tan\theta=\dfrac{4}{3};$ $\csc\theta=\dfrac{5}{4}$ $\sec\theta=\dfrac{5}{3};$ $\cot\theta=\dfrac{3}{4}$

Work Step by Step

$\sin\theta=\dfrac{opposite}{hypotenuse}=\dfrac{4}{5}$ $\cos\theta=\dfrac{adjacent}{hypotenuse}=\dfrac{3}{5}$ $\tan\theta=\dfrac{opposite}{adjacent}=\dfrac{4}{3}$ $\csc\theta=\dfrac{hypotenuse}{opposite}=\dfrac{5}{4}$ $\sec\theta=\dfrac{hypotenuse}{adjacent}=\dfrac{5}{3}$ $\cot\theta=\dfrac{adjacent}{opposite}=\dfrac{3}{4}$
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