Answer
0.499, -0.171 A
Work Step by Step
Given $I(t)=0.8 e^{-3t} \sin 10t$
The question asks for I(t) for the values of t = 0.1, 0.5
Thus substitute those t values and find y(t)
$I(t)=0.8 e^{-3(0.1)} \sin (10 * 0.1) = 0.499 A$
$I(t)=0.8 e^{-3(0.5)} \sin (10 * 0.5) = -0.171 A$
