Answer
$87, 82.7, 80, 73.9 mmHg$
Work Step by Step
Given $B(t)=80 + 7\sin \frac{\pi t}{12}$
The question asks for B(t) for the values of t = 6 (6AM), 10.5 (10:30 AM), 12 (noon), and 20 (8 PM)
Thus substitute those t values and find y(t)
$B(t)=80 + 7\sin \frac{\pi 6}{12} = 80 + 7 (1) = 87 mmHg$
$B(t)=80 + 7\sin \frac{\pi 10.5}{12}= 82.7 mmHg$
$B(t)=80 + 7\sin \frac{\pi 12}{12}= 80 + 7 (0) = 80 mmHg$
$B(t)=80 + 7\sin \frac{\pi 20}{12}= 73.9 mmHg$
