Answer
The function is even.
Work Step by Step
$f(-x) = (-x)^2 \cos{2(-x)} $
$ \because \cos{(-x) } = \cos{x}$
$\therefore f(-x) = x^2 \cos{2x} = f(x)$
The function is even.
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 5 - Section 5.2 - Trigonometric Functions of Real Numbers - 5.2 Exercises - Page 418: 72
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