Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 4 - Section 4.5 - Exponential and Logarithmic Functions - 4.5 Exercises - Page 369: 83

Answer

$f^{-1}(x)=\displaystyle \frac{\log_{2}x}{2}$

Work Step by Step

To find the inverse of y=f(x): 1. swap x and y in the expression of the function 2. solve for y 3. replace $y $ with $f^{-1}(x)$ ------------ $y=2^{2x}$ $ x=2^{2y}\qquad$... apply $\log_{2}$ to both sides $\log_{2}x=2y\qquad/\div 2$ $y=\displaystyle \frac{\log_{2}x}{2}$ $f^{-1}(x)=\displaystyle \frac{\log_{2}x}{2}$
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