## Precalculus: Mathematics for Calculus, 7th Edition

Domain: $(-\infty,1)\cup(1,+\infty)$
For a logarithmic function to be defined, its argument must be POSITIVE, So, g is defined for $x^{2}-1>0$ $x^{2}>1$ The square of a real number x is greater than 1 if $|x|>1$ (all numbers less than -1 or greater than 1) $x1$ In interval notation, $x\in(-\infty,1)\cup(1,+\infty)$ Domain: $(-\infty,1)\cup(1,+\infty)$