Answer
(a) $5$
(b) $27$
(c) $10$
Work Step by Step
According to the Laws of Logarithms we have a following expression: $x^{\log_x{a}}=a$. Roughly said, $x$ and $a$ replace each other ($x^{\log_x{a}}=a^{\log_x{x}}=a^1=a$). We will use this law to evaluate the next expression.
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(a) $3^{\log_3{5}}=5^{log_3{3}}=5^1=5$
(b) $5^{\log_5{27}}=27^{\log_5{5}}=27^1=27$
It's the same idea for natural logarithm: $e^{\ln x}=x^{\ln e}=x^1=x$
(c) $e^{\ln10}=10^{\ln e}=10^1=10$
