Answer
a.) $\ln 0.5 = x+1$
b.) $\ln t = 0.5x$
Work Step by Step
$Express$ $the$ $equation$ $in$ $logarithmic$ $form:$
a.) $e^{x+1} = 0.5$
b.) $e^{0.5x} = t$
Exponential form to natural log form: $e^b = a \rightarrow \ln a = b$ [Note: e means euler's number, NOT a variable]
a.) $e^{x+1} = 0.5$
Plug in x+1 for b and 0.5 for a
$e^{x+1} = 0.5 \rightarrow \ln 0.5 = x+1$
b.) $e^{0.5x} = t$
Plug in 0.5x for b and t for a
$e^{0.5x} = t \rightarrow \ln t = 0.5x$
