Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 3 - Section 3.7 - Polynomial and Rational Inequalities - 3.7 Exercises - Page 316: 9

Answer

$(1/2, ∞)$

Work Step by Step

$2x^3 - x^2 < 9 - 18x$ Find the roots of the function $2x^3 - x^2 +18x - 9$ $x^2(2x - 1) + 9 (2x -1)$ $(x^2 + 9) (2x-1)$ $x = 1/2$ Test numbers in between those zero values to determine if the function is negative or positive (-∞, 1/2) $ (+)(-) = (-)$ (1/2, ∞) $(+)(+) = (+)$ Thus the solution is $(1/2, ∞)$
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