Answer
$(-\infty,-1)\cup 1$
Work Step by Step
1. factorize both the numerator and the denominator:
$\frac{(x-1)^2}{(x+1)^3}\leq0$
2. The numerator will be positive except $x=1$ which is a solution.
3. Let the denominator $\lt0$, we have $x\lt-1$
4. The solution: $(-\infty,-1)\cup 1$
