Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 3 - Section 3.7 - Polynomial and Rational Inequalities - 3.7 Exercises - Page 316: 8

Answer

$(-∞, -3) U (1/2, 3)$

Work Step by Step

$2x^3 - 18x < x^2 - 9$ Find the roots of the function $2x^3 - x^2 - 18x + 9$ $x^2(2x - 1) - 9 (2x -1)$ $(x^2 - 9) (2x-1)$ $(x+3)(2x-1)(x-3)$ $x = -3, 1/2, 3$ Test numbers in between those zero values to determine if the function is negative or positive (-∞, -3) $(-)(-)(-) = (-)$ (-3, 1/2) $(+)(-)(-) = (+)$ (1/2, 3) $(+)(+)(-) = (-)$ (3, ∞) $(+)(+)(+) = (+)$ Thus the solution is $(-∞, -3) U (1/2, 3)$
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