Answer
a. $f(x) = -(x+3)^2 + 10$
b. See graph attached below
c. Maximum value = 10
Work Step by Step
$f(x) = -x^2 - 6x + 1$
a. $f(x) = -(x^2 + 6x + 9) + 1 + 9 $
$f(x) = -(x+3)^2 + 10$
b. See graph attached below
c. The maximum value is at the vertex, which is at (-3, 10) (from standard form)
Maximum value = 10
