Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 3 - Section 3.1 - Quadratic Functions and Models - 3.1 Exercises - Page 252: 34

Answer

a. $f(x) = -4(x+1/2)^2 + 4$ b. See graph attached below c. Maximum value = 4

Work Step by Step

$f(x) = -4x^2 -4x + 3$ a. $f(x) = -4( x^2 + x + 1/4) + 3 +1$ $f(x) = -4(x+1/2)^2 + 4$ b. See graph attached below c. The maximum value is at the vertex, which is at (-1/2, 4) (from standard form) Maximum value = 4
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