Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 3 - Section 3.1 - Quadratic Functions and Models - 3.1 Exercises - Page 252: 32

Answer

a. $f(x) = 2(x+2)^2 + 3$ b. See graph attached below c. Minimum value = 3

Work Step by Step

$f(x) = 2x^2 + 8x + 11$ a. $f(x) = 2( x^2 + 4x + 4) + 11 - 2(4)$ $f(x) = 2(x+2)^2 + 3$ b. See graph attached below c. The minimum value is at the vertex, which is at (-2, 3) (from standard form) Minimum value = 3
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