Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 3 - Section 3.1 - Quadratic Functions and Models - 3.1 Exercises - Page 252: 10

Answer

please see "step by step"
1509050355

Work Step by Step

Rewrite f(x) in standard form, $f(x)=a(x-h)^{2}+k$, read the vertex, (h,x) For the y-intercept, calculate f(0) For the x- intercept, solve f(x) = 0 for x. If $a>0$, parabola opens up, the vertex is a minimum point, If $a<0$, parabola opens down, the vertex is a maximum. With this information (and possible additional points) sketch a graph Read the graph for range and domain. ------------------ a. $f(x)=x^{2}+4x-1 $ $ f(x)=(x^{2}+4x) -1 \quad$... complete the square $f(x)=(x^{2}+4x+2^{2}-2^{2})-1$ $f(x)=(x^{2}+4x+2^{2})-4-5$ $f(x)=(x+2)^{2}-5$ b. vertex: $(h,k)=(-2, -5)$, a=1, opens up, the vertex is a minimum y-intercept: f(0) = $-1$ x-intercepts: f(x)=0 $(x+2)^{2}-5=0$ $(x+2)^{2}=5\qquad.../\sqrt{..}$ $x+2=\pm\sqrt{5}$ $x=-2\pm\sqrt{5}$ c. see image (one pair of additional points, either side of the vertex). d. domain: all reals, $\mathbb{R}$ range: $[-5,\infty)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.