Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 2 - Review - Exercises - Page 234: 95

Answer

$f^{-1}(x)=\dfrac{x+2}{3}$

Work Step by Step

$f(x)=3x-2$ Substitute $f(x)$ by $y$: $y=3x-2$ Solve this expression for $x$: $y+2=3x$ $\dfrac{y+2}{3}=x$ $x=\dfrac{y+2}{3}$ Interchange $x$ and $y$: $y=\dfrac{x+2}{3}$ Substitute $y$ by $f^{-1}(x)$: $f^{-1}(x)=\dfrac{x+2}{3}$
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