Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 2 - Review - Exercises - Page 234: 85

Answer

a. $6x - 3x^2 - 1$ Domain: (-∞, ∞) b. $ -9x^2 + 12x - 3$ Domain: (-∞, ∞) c. $9x -4$ Domain: (-∞, ∞) d. $ 4x - 6x^2 + 4x^3 - x^4$ Domain: (-∞, ∞)

Work Step by Step

Given $f(x) = 3x-1$ and $g(x)= 2x-x^2$, we need to find the following and their respective domains: a. f o g $f(2x-x^2) = 3(2x-x^2) - 1 = 6x - 3x^2 - 1$ Domain: (-∞, ∞) b. g o f $g(3x-1) = 2(3x-1) - (3x-1)^2 = 6x - 2 - (9x^2 - 6x + 1) = -9x^2 + 12x - 3$ Domain: (-∞, ∞) c. f o f $f ( 3x-1) = 3(3x-1) - 1 = 9x -4$ Domain: (-∞, ∞) d. g o g $g ( 2x - x^2) = 2(2x - x^2) - (2x - x^2) ^ 2 = 4x - 2x^2 - x^4 + 4x^3 - 4x^2$ $= 4x - 6x^2 + 4x^3 - x^4$ Domain: (-∞, ∞)
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