Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 2 - Review - Exercises - Page 231: 2

Answer

$f(x)=\dfrac{x}{2}+9$

Work Step by Step

"Divide by $2$, then add $9$" Let $x$ be the independent variable for $f$ First, divide $x$ by $2$: $\dfrac{x}{2}$ Now, add $9$ to the fraction: $\dfrac{x}{2}+9$ The function described is $f(x)=\dfrac{x}{2}+9$
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