Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 2 - Review - Exercises - Page 231: 10

Answer

$f(5)=1$ $f(9)=4-\sqrt{21}\approx-0.583$ $f(a+2)=4-\sqrt{3a}$ $f(-x)=4-\sqrt{-3x-6}$ $f(x^{2})=4-\sqrt{3x^{2}-6}$

Work Step by Step

$f(x)=4-\sqrt{3x-6};$ $f(5),$ $f(9),$ $f(a+2),$ $f(-x),$ $f(x^{2})$ Substitute $x$ by each corresponding value and simplify: $f(5)=4-\sqrt{3(5)-6}=4-\sqrt{15-6}=4-\sqrt{9}=4-3=1$ $f(9)=4-\sqrt{3(9)-6}=4-\sqrt{27-6}=4-\sqrt{21}\approx-0.583$ $f(a+2)=4-\sqrt{3(a+2)-6}=4-\sqrt{3a+6-6}=4-\sqrt{3a}$ $f(-x)=4-\sqrt{3(-x)-6}=4-\sqrt{-3x-6}$ $f(x^{2})=4-\sqrt{3x^{2}-6}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.