Answer
$f(x)=2^x, a=5$
Work Step by Step
As $32=2^5$, let $f(x)=2^x$, we have:
$$f'(5)=\lim_{x\to 5}\frac{2^x-2^5}{x-5}=\lim_{x\to 5}\frac{2^x-32}{x-5}$$
Thus we have $f(x)=2^x, a=5$
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 13 - Section 13.3 - Tangent Lines and Derivatives - 13.3 Exercises - Page 922: 34
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
