Answer
1, 3, 5, 11, 21, 43, 85
Work Step by Step
$a_{1}=1,$
$a_{2}=3,\qquad a_{n}=a_{n-1}+2a_{n-2}$,
$a_{3}=a_{2}+2a_{1}=3+2(1)=5$,
$a_{4}=a_{3}+2a_{2}=5+2(3)=11$,
$a_{5}=a_{4}+2a_{3}=11+2(5)=21$,
$a_{6}=a_{5}+2a_{4}=21+2(11)=43$,
$a_{7}=a_{6}+2a_{5}=43+2(21)=85$