Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 12 - Review - Exercises - Page 889: 8

Answer

$\displaystyle \frac{1}{2},\ \displaystyle \frac{1}{6},\ \displaystyle \frac{1}{24},\ \displaystyle \frac{1}{120},\ \displaystyle \frac{1}{720},\ \displaystyle \frac{1}{5040}$

Work Step by Step

$a_{1}=1, \qquad a_{n}=\displaystyle \frac{a_{n-1}}{n}$ $a_{2}=\displaystyle \frac{a_{1}}{2}=\frac{1}{2}$, $a_{3}=\displaystyle \frac{a_{2}}{3}=\frac{1}{3(2)}=\frac{1}{6}$, $a_{4}=\displaystyle \frac{a_{3}}{4}=\frac{1}{4(6)}=\frac{1}{24}$, $a_{5}=\displaystyle \frac{a_{4}}{5}=\frac{1}{5(24)}=\frac{1}{120}$, $a_{6}=\displaystyle \frac{a_{5}}{6}=\frac{1}{6(120)}=\frac{1}{720}$, $a_{7}=\displaystyle \frac{a_{6}}{7}=\frac{1}{7(720)}=\frac{1}{5040}$
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