Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 12 - Review - Exercises - Page 889: 3

Answer

$a_{1}=0$, $\ \ a_{2}=\displaystyle \frac{1}{4}$, $\ \ a_{3}=0$, $a_{4}=\displaystyle \frac{1}{32}$, $a_{10}=\displaystyle \frac{1}{500}$

Work Step by Step

$a_{1}=\displaystyle \frac{(-1)^{1}+1}{1^{3}}=0$, $a_{2}=\displaystyle \frac{(-1)^{2}+1}{2^{3}}=\frac{2}{8}=\frac{1}{4}$, $a_{3}=\displaystyle \frac{(-1)^{3}+1}{3^{3}}=0$, $a_{4}=\displaystyle \frac{(-1)^{4}+1}{4^{3}}=\frac{2}{64}=\frac{1}{32}$, $a_{10}=\displaystyle \frac{(-1)^{10}+1}{10^{3}}=\frac{2}{1000}=\frac{1}{500}$
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