Answer
1, 4, 9, 16, 25, 36, 49
Work Step by Step
$a_{1}=1$
$\ \ \ a_{n}=a_{n-1}+2n-1$
$a_{2}=a_{1}+4-1=4$,
$a_{3}=a_{2}+6-1=9$,
$a_{4}=a_{3}+8-1=16$,
$a_{5}=a_{4}+10-1=25$,
$a_{6}=a_{5}+12-1=36$,
$a_{7}=a_{6}+14-1=49$.
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 12 - Review - Exercises - Page 889: 7
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