Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 11 - Section 11.1 - Parabolas - 11.1 Exercises - Page 789: 59

Answer

(a) $x^2=-2y$. $x^2=-4y, x^2=-16y$ and $x^2=-32y$ (b) See graphs and explanations below.

Work Step by Step

(a) Since the vertex is at the origin and the directrixes are parallel to the x-axis, we can write the general equation as $x^2=4py$ with directrix at $y=-p$. Given $y=\frac{1}{2}$ as the directrix, we have $p=-\frac{1}{2}$ and the equation becomes $x^2=-2y$. Similarly, the equations for others directrixes are $x^2=-4y, x^2=-16y$ and $x^2=-32y$ for drectrixes of $y=1, 4$ and $8$ respectively. (b) See graphs, we can conclude that with the increasing of the absolution value of the directrix, the opening of the parabola will become wider.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.