Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 11 - Section 11.1 - Parabolas - 11.1 Exercises - Page 789: 53

Answer

$y^{2}=-3x$

Work Step by Step

Given:$|4p|=3; p\lt 0$ This gives: $p=-\dfrac{3}{4}$ The general form of the equation of a parabola which opens right is $y^{2}= 4px$ Thus, the equation of the parabola becomes: $y^{2}= (4)(-\dfrac{3}{4})(x)$ $\implies y^{2}=-3x$
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