Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 11 - Section 11.1 - Parabolas - 11.1 Exercises - Page 789: 51

Answer

$y^{2}= -16x$

Work Step by Step

Given: The equation of directrix is $x=-p=4$ This gives: $p=-4$ This shows that the parabola opens to the right. The general form of the equation of a parabola which opens to the right is $y^{2}= 4px$ Thus, the equation of the parabola becomes: $y^{2}= 4(-4)x$ $\implies y^{2}= -16x$
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