Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 10 - Section 10.1 - Systems of Linear Equations in Two Variables - 10.1 Exercises - Page 690: 73

Answer

John's Time = 2.25 hours Mary's Time = 2 hours

Work Step by Step

x = John's Time y = Mary's Time c = John's Distance d = Mary's Distance x = c/60 y = d/40 c = d + 35 d = 40(x + .25) Expand d and plug into c: c = 40x + 45 Now plug c into x and multiply both sides by 60: 60x = 40x + 45 Divide all terms by 60 and simplify: x = 2/3x + 3/4 Subtract 2/3x from both sides: 1/3x = 3/4 Divide both sides by 1/3: x = 9/4 x = 2.25 John travelled for 2.25 hours. Mary travelled for 15 minutes less, so she drove for 2 hours.
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