Answer
$(10, -12)$
Work Step by Step
Given system is-
$4x +2y$ = $16$ __ eq.1
$x -5y$ = $70$
or
$x $ = $70 + 5y$ __ eq.2
Substituting for $x$ in eq.1
$4(70 + 5y) +2y$ = $16$
i.e. $280 + 20y +2y$ = $16$
i.e. $22y$ = $16-280$ = $-264$
i.e. $y$ = $\frac{-264}{22}$
i.e. $y$ = $-12$
Substituting for $y$ in eq.2
$x $ = $70 + 5(-12)$
$x $ = $70 -60$ = $10$
Thus $(10, -12)$ is the solution of given system.