Answer
$(3,-1)$
Work Step by Step
Given system is-
$2x -3y$ = $9$ __ eq.1
$4x +3y$ = $9$ __ eq.2
Adding eq.1 and eq.2 -
$2x -3y+4x +3y)$ = $9+9$
i.e. $6x$ = $18$
i.e. $x$ = $\frac{18}{6}$
i.e. $x$ = $3$
Substituting for $x$ in eq.2
$4(3) +3y$ = $9$
i.e. $3y$ = $9-12$ =$-3$
i.e. $y$ = $-1$
Thus $(3,-1)$ is the solution of given system.