Answer
$(3, 5)$
Work Step by Step
Given system is-
$-x +y$ = $2$ __ eq.1
$4x -3y$ = $-3$ __ eq.2
Multiplying eq.1 by '3'-
$-3x +3y$ = $6$ __ eq.3
Adding eq.2 and eq.3 -
$4x -3y-3x +3y$ = $-3+6$
i.e. $x$ = $3$
Substituting for $x$ in eq.1
$-3 +y$ = $2$
i.e. $y$ = $2+3$
i.e. $y$ = $5$
Thus $(3, 5)$ is the solution of given system.