Answer
$(2,1)$
Work Step by Step
Given system is-
$x +3y$ = $5$ __ eq.1
$2x -y$ = $3$ __ eq.2
Multiplying eq.2 by '3'-
$6x -3y$ = $9$ __ eq.3
Adding eq.1 and eq.3 -
$x +3y+6x -3y$ = $5+9$
i.e. $7x$ = $14$
i.e. $x$ = $\frac{14}{7}$
i.e. $x$ = $2$
Substituting for $x$ in eq.1
$2 +3y$ = $5$
i.e. $3y$ = $5-2$ =$3$
i.e. $y$ = $1$
Thus $(2,1)$ is the solution of given system.