Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 10 - Section 10.1 - Systems of Linear Equations in Two Variables - 10.1 Exercises - Page 688: 25

Answer

$(2,1)$

Work Step by Step

Given system is- $x +3y$ = $5$ __ eq.1 $2x -y$ = $3$ __ eq.2 Multiplying eq.2 by '3'- $6x -3y$ = $9$ __ eq.3 Adding eq.1 and eq.3 - $x +3y+6x -3y$ = $5+9$ i.e. $7x$ = $14$ i.e. $x$ = $\frac{14}{7}$ i.e. $x$ = $2$ Substituting for $x$ in eq.1 $2 +3y$ = $5$ i.e. $3y$ = $5-2$ =$3$ i.e. $y$ = $1$ Thus $(2,1)$ is the solution of given system.
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