Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 10 - Review - Exercises - Page 770: 7

Answer

x = -3 x = 2

Work Step by Step

1. Since both equations are set equal to y, this means that you can set both equations equal to each other, meaning 6 + x = $x^{2}$ +2x. 2. I brought all the terms to the right hand of the equation but you can also do the left hand. 3. Bringing all terms to right side gives us 0 = $x^{2}$ +2x - 6 - x. 4. Simplify, 0 = $x^{2}$ +x -6 5. Now factor, (x+3)(x-2)=0 6. Set both terms equal to 0, x + 3 = 0 ; x - 2 = 0 7. Simplify, x = -3 ; x = 2
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