Answer
No Solutions.
See graph below.
Work Step by Step
Given the system of equations:
1. $2x - y = 1$
2. $x + 3y = 10$
3. $3x + 4y = 15$
It asks to find all solutions and to graph.
Substitute $x = 10-3y$ from equation 2 into equations 1 and 3
1. $2(10 - 3y) - y = 1$
$20 - 6y - y = 1$
$-7y = -19$
$y = 19/7$
3. $3(10 - 3y) + 4y = 15$
$30 - 9y + 4y = 15$
$-5y = -15$
$y = 3$
Since y has two different solutions, then there are no solutions present. The lines do not intersect at one point
See graph below.
The red line is graph 1; the blue line is graph 2; the black line is graph 3.
