Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 10 - Review - Exercises - Page 770: 35

Answer

$(\frac{4-4t}{3}, \frac{5t-2}{3}, t)$

Work Step by Step

Step 1. Set up the augmented matrix of the system of equations: $\begin{array} \\A=\\ \end{array} \begin{bmatrix} 1&-1&3&2\\ 2&1&1&2\\ 3&0&4&4 \end{bmatrix} \begin{array} \\ \\R_2-2R_1\to R_2\\R_3-3R_1\to R_3\\ \end{array}$ Step 2. Do the row operations indicated on the right side of the matrix: $\begin{array} \\A=\\ \end{array} \begin{bmatrix} 1&-1&3&2\\ 0&3&-5&-2\\ 0&3&-5&-2 \end{bmatrix} \begin{array} \\ \\ \\ \\ \end{array}$ Step 3. The last two rows are the same. Let $z=t$, we have $3y-5t=-2$ or $y=\frac{5t-2}{3}$. Use row-1 to get $x-\frac{5t-2}{3}+3t=2$ or $x=\frac{4-4t}{3}$ Step 4. Conclusion: the solutions are $(\frac{4-4t}{3}, \frac{5t-2}{3}, t)$
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