Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.9 - The Coordinate Plane; Graphs of Equations; Circles - 1.9 Exercises - Page 103: 75

Answer

x-intercepts: 0 and 4 y-intercept: 0

Work Step by Step

RECALL: (i) The x-intercept is the value of x w hen y=0. (ii) The y-intercept is the value of y when x=0. Based on the given graph of the function, it appears that the function has: x-intercept/s: 0 and 4 y-intercept: 0 Check if these are the actual intercepts by substituting each one to the given equation: For x=0: $y=4x-x^2 \\y=4(0)-0^2 \\y=0$ For x=4: $y=4x-x^2 \\y=4(4)-4^2 \\y=16-16 \\y=0$ Thus, 0 and 4 are x-intercepts of the equation. Since (0, 0) is on the graph of the equation, the 0 is a y-intercept.
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