Answer
SOLUTION
$x\leq-9$ and $x\geq7$
GRAPH
In the real number line put and -9 with a close cirlce and draw a line towards $-\infty$. Then put a 7 with a close circle and draw a line pointin towards $\infty$.
Work Step by Step
$\mid\frac{x+1}{2}\mid \geq4$
So you divide it in two to take the absolute value away
$\frac{x+1}{2} \leq-4$ Or $\frac{x+1}{2} \geq4$.
First let’s solve one at a time
$$\frac{x+1}{2} \leq-4$$ $$x+1\leq-8$$ $$x\leq-9$$
Now the second one
$$\frac{x+1}{2} \geq4$$ $$x+1\geq8$$ $$x\geq7$$
So we have two solutions
$x\leq-9$ and $x\geq7$
GRAPH
In the real number line put and -9 with a close cirlce and draw a line towards $-\infty$. Then put a 7 with a close circle and draw a line pointin towards $\infty$.
