## Precalculus: Mathematics for Calculus, 7th Edition

$(-\infty, -18)$ Refer to the attached image for the graph.
For easier work, get rid of the fractions by multiplying the LCD of 6 to both sides to have: $\\6(\frac{1}{3}x +2) \lt 6(\frac{1}{6}x-1) \\2x+12 \lt x-6$ Subtract $x$ to both sides to have: $\\2x+12-x \lt x-6-x \\x+12 \lt -6$ Subtract $12$ to both sides to have: $\\x+12-12 \lt -6-12 \\x \lt -18$