## Precalculus: Mathematics for Calculus, 7th Edition

$(-\infty, -1]$ Refer to the attached image below for the graph.
The given inequality can be written as $\\4-3x \le -1(1+8x)$ Distribute $-1$ to have: $\\4-3x \le -1 -8x$ Add $8x$ to both sides to have: $\\4-3x+8x \le -1-8x+8x \\4+5x \le -1$ Subtract 4 to both sides to have: $\\4+5x-4 \le -1 - 4 \\5x \le -5$ Divide 5 to both sides to have: $x \le -\frac{5}{5} \\x \le -1$