Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.8 - Inequalities - 1.8 Exercises - Page 89: 42


$(-\infty, -3) \cup (-2, +\infty)$ Refer to the attached image below for the graph.

Work Step by Step

All nonzero terms are on the left side of the inequality. Factor the trinomial to have: $(x+3)(x+2)\gt 0$ Now that the nonzero side of the inequality is already factored, proceed to finding the intervals for the given inequality. The factors of the nonzero side are $(x+2)$ and $(x+3)$. These factors are zero when $x=-2 \text{ and } -3$, respectively. These numbers divide the number line into the following intervals: $(−\infty, -3),(-3, -2), (-2, +\infty)$ Make a diagram by using test points to determine the sign of each factor in each interval. (refer to the attached image below). It can be seen from the diagram that the given inequality is satisfied on the intervals $(-\infty, -3), \text{ and } (-2, +\infty)$. The inequality involves $\lt$ so the endpoints do not satisfy the inequality. Thus, the solution is $ (-\infty, -3) \cup (-2, \infty)$.
Small 1497579380
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.