## Precalculus: Mathematics for Calculus, 7th Edition

The 3 ways to solve a quadratic equation are 1) Factoring $$x^{2}+4x+4$$ $$(x+2)(x+2)$$ 2) Quadratic Formula $$\frac{-b+/-\sqrt (b^{2}-4(ac))}{2a}$$ 3) Completing the Square $$x^{2}+12x+32=0$$ $$x^{2}+12x=-32$$ Now you take the b which is 12 divide by 2 and square it. $(\frac{12}{2})^{2}=36$ The result add it on both sides to keep the balance. $$x^{2}+12x+36=-32+36$$ $$x^{2}+12x+36=4$$ Now factor it. $$(x+6)(x+6)=4$$ $$\sqrt (x+6)^{2}=\sqrt 4$$ Now we will divide this into two negative and positive. $(x+6)=2$ and $(x+6)=-2$ $x=-4 and x=-8$