Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Review - Concept Check - Page 133: 21

Answer

Quadratic Formula: $\frac{-b+/-\sqrt {b^2-4ac}}{2a}$ $x=-3(+/-)\sqrt {10}$

Work Step by Step

The formula for the average quadratic equation is given above. $a=1$ (your $x^2$ coefficient) $b=6$ (your $x$ coefficient) $c=-1$ (the lone number) Plug in these values for $a, b, c$. $\frac{-6+/-\sqrt {6^2-4(1)(-1)}}{2(1)}$ $\frac{-6+/-\sqrt {40}}{2}$ $\frac{-6(+/-)2\sqrt {10}}{2}$ $x=-3(+/-)\sqrt {10}$
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